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	<title>Comments on: Differentiable Once But Not Twice</title>
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	<description>Math is exciting... math is fun!</description>
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		<title>By: Mike</title>
		<link>http://leedsmathgeeks.com/2010/differentiable-once-but-not-twice/comment-page-1/#comment-10095</link>
		<dc:creator>Mike</dc:creator>
		<pubDate>Fri, 02 Sep 2011 15:38:23 +0000</pubDate>
		<guid isPermaLink="false">http://leedsmathgeeks.com/?p=136#comment-10095</guid>
		<description>Look at the graph of f(x)=x^x evaluated at 0.  The value is 1.</description>
		<content:encoded><![CDATA[<p>Look at the graph of f(x)=x^x evaluated at 0.  The value is 1.</p>
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		<title>By: Vlad</title>
		<link>http://leedsmathgeeks.com/2010/differentiable-once-but-not-twice/comment-page-1/#comment-6471</link>
		<dc:creator>Vlad</dc:creator>
		<pubDate>Sun, 08 May 2011 11:06:54 +0000</pubDate>
		<guid isPermaLink="false">http://leedsmathgeeks.com/?p=136#comment-6471</guid>
		<description>@Chloe:

It&#039;s one of those things that isn&#039;t obvious from the definition, so we tend to define it in whatever way seems more sensible depending on what we&#039;re working with.

A similar situation is 0/0. It&#039;s indeterminate, so if you come across it as the y-value of a function, you don&#039;t really know what the answer is. But based on the points around it, there&#039;s probably a most sensible value it should be. For example, (5x^2)/x is 0/0 at x = 0, but it makes most sense to define it to be equal to 0 there, because that&#039;s the limit when we approach it from either side. (This explanation isn&#039;t exactly right, but I&#039;m using it for the analogy.)

So, when it comes to 0^0, it usually makes sense to define it as being equal to 0. (Though I think I&#039;ve heard it sometimes makes sense to define it as 1, too.)

Hope this helps.</description>
		<content:encoded><![CDATA[<p>@Chloe:</p>
<p>It&#8217;s one of those things that isn&#8217;t obvious from the definition, so we tend to define it in whatever way seems more sensible depending on what we&#8217;re working with.</p>
<p>A similar situation is 0/0. It&#8217;s indeterminate, so if you come across it as the y-value of a function, you don&#8217;t really know what the answer is. But based on the points around it, there&#8217;s probably a most sensible value it should be. For example, (5x^2)/x is 0/0 at x = 0, but it makes most sense to define it to be equal to 0 there, because that&#8217;s the limit when we approach it from either side. (This explanation isn&#8217;t exactly right, but I&#8217;m using it for the analogy.)</p>
<p>So, when it comes to 0^0, it usually makes sense to define it as being equal to 0. (Though I think I&#8217;ve heard it sometimes makes sense to define it as 1, too.)</p>
<p>Hope this helps.</p>
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		<title>By: Chloe</title>
		<link>http://leedsmathgeeks.com/2010/differentiable-once-but-not-twice/comment-page-1/#comment-6400</link>
		<dc:creator>Chloe</dc:creator>
		<pubDate>Thu, 05 May 2011 23:45:31 +0000</pubDate>
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		<description>I was wondering if you could possibly address the 0^0 conundrum. Nobody seems to be able to say whether it is 0 or 1. I&#039;m incredibly confused!</description>
		<content:encoded><![CDATA[<p>I was wondering if you could possibly address the 0^0 conundrum. Nobody seems to be able to say whether it is 0 or 1. I&#8217;m incredibly confused!</p>
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